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Zeeshan got 25/30 marks on the first lab assignment, 50/50 marks on the second lab assignment, and 40/50 on the third lab assignment. he also got of 35/50 in quizzes and 9/10 in homework. on the first test, he got an 85% and on the second test he got 95%. what will be zeeshan's final grade?

User Ling Zhong
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1 Answer

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Final answer:

Zeeshan's final grade is calculated by converting his scores on assignments, quizzes, homework, and tests into percentages and averaging them, resulting in 86.19%. The regression equation provided does not seem to be applicable in this context. For the true-false quiz probability, the binomial probability formula would be used.

Step-by-step explanation:

To calculate Zeeshan's final grade, we first need to sum up all the marks obtained and then divide by the total marks possible. Zeeshan's lab assignment scores are 25/30, 50/50, and 40/50, quiz score is 35/50, and the homework score is 9/10.

First, we convert these into percentages and then into points, assuming each component has the same weight. For the first lab assignment, the score is ≈25/30 = 83.33%, for the second lab assignment, it's 100% as he got all the points, and for the third lab assignment, it is 40/50 = 80%. The quiz score is 35/50 = 70%, and the homework score is 9/10 = 90%. For the first test, Zeeshan got 85%, and for the second test, he got 95%.

The final grade is the average of all these percentages:

(83.33 + 100 + 80 + 70 + 90 + 85 + 95) / 7 = 86.19%

Therefore, Zeeshan's final grade would be 86.19%.

Considering the provided regression equation, 173.51 + 4.83(73) = 179.08, if a student scores a 90 on the third exam, the final exam score prediction is 173.51 + 4.83(90) = 607.2, which does not make sense in the context of exam scores, so there might be a misunderstanding of how this equation should be applied.

The probability of guessing at least 7 out of 10 correct answers on a true-false quiz, without studying, is calculated using the binomial probability formula.
The number of ways to choose k successes from n trials is given by 'n choose k' (the binomial coefficient) and the probability of k successes is this coefficient multiplied by the probability of success raised to the kth power, and the probability of failure raised to the (n-k)th power.

User Doctorram
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