Question

You are given 5.0 ml of a stock solution of tartrazine that is 0.090 molarity. you add 4.0 ml of deionized water to the 5 ml of sock solution. what is the concentration of your diluted sample in molarity?

Answer 1

The concentration of the diluted tartrazine solution is 0.050 Molarity, calculated using the dilution equation C1V1 = C2V2.

Step-by-step explanation:

Dilution of Concentrated Solutions:

To calculate the concentration of your diluted sample in molarity, you can use the dilution equation C1V1 = C2V2, where C1 is the initial concentration of the stock solution, V1 is the volume of the stock solution, C2 is the concentration of the diluted solution, and V2 is the total volume of the diluted solution.

The initial concentration (C1) of tartrazine is given as 0.090 M, and the initial volume (V1) is 5.0 mL. The volume of water added is 4.0 mL, so the final volume (V2) will be (5.0 mL + 4.0 mL) = 9.0 mL. To find the final concentration (C2), rearrange the equation to solve for C2: C2 = (C1V1) / V2.

Substituting the given values: C2 = (0.090 M × 5.0 mL) / 9.0 mL which simplifies to C2 = 0.050 M. Therefore, the concentration of the diluted tartrazine solution is 0.050 Molarity.