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Write a function of the geometric sequence with a starting term of 128 and a common ratio of 1/2 . find the fifth term.

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Final answer:

The fifth term of the geometric sequence with a starting term of 128 and a common ratio of ½ is found using the formula an = a1 × r(n-1), resulting in a fifth term of 8.

Step-by-step explanation:

The student has asked for a function of a geometric sequence with a starting term of 128 and a common ratio of ½. A geometric sequence can be defined by the formula an = a1 × r(n-1), where an is the nth term, a1 is the first term, r is the common ratio, and n is the term number. To find the fifth term, we would plug 5 into our formula as n.

To calculate the fifth term, we use the following steps:

  1. Identify the first term (a1) of the sequence, which is 128.
  2. Determine the common ratio (r), which is ½.
  3. Substitute these values into the formula along with the term number (n = 5): a5 = 128 × (½)(5-1).
  4. Simplify the expression: a5 = 128 × (½)4 = 128 × ¼ = 128 × 0.0625.
  5. Calculate the final value: a5 = 8.

Therefore, the fifth term of the geometric sequence is 8.

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