Final answer:
The reaction between methylamine (CH₃NH₂), a weak base, and chloric acid (HClO₃), a strong acid, forms methylammonium chloride (CH₃NH₃⁺) and the spectator ion chlorate (ClO₃⁺), resulting in a slightly acidic solution.
Step-by-step explanation:
When a weak base like methylamine (CH₃NH₂) reacts with a strong acid such as chloric acid (HClO₃), the base accepts a proton from the acid. The chemical reaction, showing the products, is as follows:
CH₃NH₂ (aq) + HClO₃ (aq) → CH₃NH₃⁺ (aq) + ClO₃⁺ (aq)
In this reaction, methylamine (CH₃NH₂), a weak base, reacts with chloric acid (HClO₃), a strong acid, to form methylammonium chloride (CH₃NH₃⁺) and the conjugate base chlorate (ClO₃⁺). The ClO₃⁺ ion is a spectator ion and does not participate significantly in the reaction. This type of reaction typically results in a solution that is slightly acidic due to the formation of the weak acid (methylammonium ion).