Final answer:
The mass percent of bromine in zinc bromate, Zn(BrO₃)₂, is calculated to be approximately 25%, with zinc being the predominant element by mass.
Step-by-step explanation:
To calculate the mass percent of bromine in zinc bromate, Zn(BrO₃)₂, we first need to find the molar mass of the compound and the total mass of bromine within it.
The molar mass of zinc bromate can be calculated by adding the molar masses of all the atoms in the formula:
- Zn = 65.38 g/mol
- Br = 79.904 g/mol
- O = 16.00 g/mol
The molar mass of Zn(BrO₃)₂ is 1(65.38) + 2(79.904 × 3) + 6(16.00) = 65.38 + 479.424 + 96 = 640.804 g/mol.
Next, we calculate the total mass of bromine in the compound: 2 × 79.904 g/mol = 159.808 g/mol.
Finally, the mass percent of bromine in zinc bromate is given by:
(Total mass of Br / Molar mass of Zn(BrO₃)₂) × 100 = (159.808 g/mol / 640.804 g/mol) × 100 ≈ 25%.
The calculations make sense because the compound is mostly zinc by mass even after accounting for the presence of bromine and oxygen.