Final answer:
The coordinates of the point where the line y=15x-7 crosses the y-axis are (0, -7), found by substituting x with 0 in the equation and solving for y.
Step-by-step explanation:
The question asks to find the coordinates of the point where the line represented by the equation y=15x-7 crosses the y-axis.
In the context of the slope and the algebra of straight lines, the equation of a line is generally written in the form y = mx + b, where 'm' represents the slope of the line, and 'b' represents the y-intercept, which is the point where the line crosses the y-axis.
The slope indicates how steep the line is and is calculated by the rise over the run, or the amount the y-coordinate changes for a given change in the x-coordinate.
To find the y-intercept, we need the value of y when x is 0.
Plugging x = 0 into the equation y=15x-7, we get y = 15(0) - 7, which simplifies to y = -7.
Therefore, the coordinates of the point where the line crosses the y-axis are (0, -7).
This point is found by plotting the value of y when x is 0, which results in a point located exactly on the y-axis at -7 units from the origin.