Question

Assume you have a child with a homozygous nontaster, what is the probability that your child will be able to taste bitter compounds either mildly or strongly Upload an image of an appropriate Punnett square to support your answer.

Answer 1

The probability of a homozygous nontaster child to taste bitter compounds either mildly or strongly is 50% if one parent is a mild taster (heterozygous) and the other is a homozygous nontaster.

Step-by-step explanation:

If a child is a homozygous nontaster for a bitter compound, the likelihood that they will be able to taste bitter compounds either mildly or strongly depends on the genotype of the other parent. Assuming incomplete dominance and that one parent is heterozygous while the other is homozygous recessive (nontaster), we can use a Punnett square to determine the possible genotypes of their offspring.

Let P represent the dominant allele for tasting PTC strongly, p represent the heterozygous condition (mild taster), and pp represent the homozygous recessive condition (nontaster). If one parent is Pp (mild taster) and the other is pp (nontaster), their combinations could lead to offspring with genotypes Pp (mild taster) and pp (nontaster).

The probability for their child to be able to taste PTC either mildly or strongly would be 50%, as there is a 1:1 ratio of mild tasters to nontasters in their potential offspring.