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In a 2cnf-formula, each clause is an OR of at most two terms, and the clauses are combined with ANDs. For example, (x1 ∨ x2) ∧ (×3 ∨ ×4) ∧ (x1 ∨ ×3) is a 2cnf-formula. x

Define the language 2SAT of satisfiable 2cnf-formulas:
2SAT = {< ϕ > ❘ ϕ is a satisfiable 2cnf-formula }.
Show that 2SAT is in P.

User Joshgo
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Final answer:

2SAT is a language of satisfiable 2cnf formulas that is in the complexity class P, as it can be solved using a polynomial-time algorithm via implication graphs and the analysis of strongly connected components.

Step-by-step explanation:

The language 2SAT consists of satisfiable 2cnf formulas, where each clause is an OR of at most two literals, and the clauses are combined with ANDs. To show that 2SAT is in the complexity class P, one could use the polynomial-time algorithm based on graph theory that converts the formula into an implication graph and then checks for the existence of strongly connected components with both a variable and its negation. If none are found, the formula is satisfiable, proving that 2SAT can be solved in polynomial time and hence is in P.

The language 2SAT consists of satisfiable 2cnf-formulas. To show that 2SAT is in P, we need to demonstrate that it can be solved in polynomial time. This can be done using the algorithm known as the Strongly Connected Components (SCC) algorithm. The SCC algorithm can determine if a 2cnf-formula is satisfiable or not by identifying whether contradiction exists within the formula. Since the SCC algorithm has a polynomial time complexity, it proves that 2SAT is in P.

User YourGoodFriend
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