Final answer:
Without the expression from Part D, we cannot compute the exact vertical velocity of the car at t=0.25 seconds. The given parameters suggest a motion combining exponential decay with oscillation, typically represented by an exponentially decaying cosine function.
Step-by-step explanation:
To evaluate the numerical value of the vertical velocity of the car at time t=0.25 seconds, we would need the expression from Part D of the original question, which is not provided here. However, based on the given parameters (initial position y0=0.75 meters, exponential decay rate α=0.95s⁻¹, and angular frequency ω=6.3s⁻¹), it seems that the motion described is a combination of exponential decay and oscillatory motion, which might be represented by an equation of the form y(t) = y0 e^{-αt}cos(ωt).
Typically, to find vertical velocity, we would take the first derivative of the position function with respect to time. If we assume the position function is indeed as suggested above, the derivative of that function with respect to time would give us the expression for vertical velocity. However, without the exact expression from Part D, we cannot compute the exact numerical value.