Question

How many degrees will 340 J raise the temperature of 6.8 g of water? (Refer

to table of constants for water.)
A. 12°C
B. 81°C
C. 50°C
D. 28°C

Answer 1

Using the specific heat capacity formula, 340 J of heat would raise the temperature of 6.8 g of water by approximately 11.95°C, so the closest answer choice is A. 12°C.

Step-by-step explanation:

To solve for the temperature increase of water when heat is added, we can use the specific heat capacity formula: Q = mcΔt, where Q is the amount of heat in joules, m is the mass of the water in grams, c is the specific heat capacity (4.184 J/g°C for water), and Δt is the change in temperature in degrees Celsius.

To find the change in temperature (Δt), we rearrange the formula to Δt = Q / (mc). For this problem, 340 J of heat will raise the temperature of 6.8 g of water. Plugging in the values:. Δt = 340 J / (6.8 g × 4.184 J/g°C). Δt = 340 J / (28.4512 J/°C). Δt ≈ 11.95°C. Therefore, the closest answer choice is A. 12°C.