Final answer:
To prepare a 2.00 L, 0.100 M K₂CrO₄ solution from 1.75 M stock, measure 114.3 mL of the stock and dilute it to a final volume of 2.00 L.
Step-by-step explanation:
To prepare 2.00 L of 0.100 M K₂CrO₄ from a 1.75 M stock solution, one must use the dilution formula M1V1 = M2V2, where M1 and M2 are the molarities of the initial and final solutions, respectively, and V1 and V2 are the volumes of the initial and final solutions, respectively. In this case, M1 is 1.75 M (the molarity of the stock solution), V2 is 2.00 L (the final volume of the solution we want to prepare), and M2 is 0.100 M (the final molarity of the solution). Plugging these values into the formula, we get:
V1 = (M2 × V2) / M1
V1 = (0.100 M × 2.00 L) / 1.75 M
V1 = 0.1143 L
Thus, you would need to measure 114.3 mL of the 1.75 M K₂CrO₄ stock solution and dilute it with water to reach a final volume of 2.00 L.