Final answer:
The volume of the hyperbaric chamber containing 2300 g of O₂ at 25 °C and 3.0 atm is approximately 5700 liters, calculated using the ideal gas law after converting the given mass to moles and the temperature to Kelvin.
Step-by-step explanation:
To calculate the volume of the hyperbaric chamber containing 2300 g of O₂ at 25 °C and 3.0 atm, we can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/K·mol), and T is the temperature in Kelvin.
First, we need to convert the mass of O₂ to moles. Oxygen has a molar mass of 32.00 g/mol, so:
n = mass / molar mass = 2300 g / 32.00 g/mol = 71.875 moles of O₂
Next, convert the temperature to Kelvin:
T = 25 °C + 273.15 = 298.15 K
Now, insert the values into the ideal gas law equation:
PV = nRT
V = nRT / P = (71.875 mol) * (0.0821 L·atm/K·mol) * (298.15 K) / 3.0 atm
V ≈ 5745.77 L
Therefore, the volume of the hyperbaric chamber is approximately 5745.77 liters, which we can express using two significant figures as 5700 liters.