Final answer:
To find the volume of a 0.0225M KCl solution containing 55.8g of KCl, we first calculate the number of moles of KCl as 55.8g divided by its molar mass (74.55 g/mol) to get 0.748 moles. Next, we divide these moles by the molarity (0.0225M) to find the volume, which is 33.24 liters.
Step-by-step explanation:
The question asks us to determine how much of a 0.0225M KCl solution would contain exactly 55.8g of KCl.
To find the answer, we need to calculate the number of moles of KCl that 55.8g represents and then use the molarity of the solution to find the volume.
The molecular weight of KCl is approximately 74.55 g/mol. Thus, the number of moles of KCl is calculated as follows:
Number of moles = mass (g) ÷ molar mass (g/mol)
= 55.8g ÷ 74.55g/mol
= 0.748 moles
Now, using the molarity of the solution (M), which is moles of solute per liter of solution, we can find the volume required to contain these moles:
Volume = number of moles ÷ molarity
= 0.748 moles ÷ 0.0225M
= 33.24 liters