Question

Loads of freight are pulled behind a train engine. the loads are different each day of the week. masses of loads day of trip mass (kg) monday 125,750 tuesday 115,100 wednesday 126,900 thursday 113,700 friday 125,850 the freight has the same acceleration as it starts moving each day. order the days to show the size of the force applied to the freight.

Answer 1

The size of the force applied to the freight on different days can be determined using the formula F = ma, where F is the force, m is the mass, and a is the acceleration.

Step-by-step explanation:

In order to determine the size of the force applied to the freight on different days, we need to calculate the force using the formula F = ma, where F is the force, m is the mass, and a is the acceleration.

First, we need to convert the masses of the loads to kilograms. The masses are: Monday - 125,750 kg, Tuesday - 115,100 kg, Wednesday - 126,900 kg, Thursday - 113,700 kg, Friday - 125,850 kg.

1. Monday: F = ma = 125,750 kg × 5.00 × 10^-2 m/s² = 6287.5 N
2. Tuesday: F = ma = 115,100 kg × 5.00 × 10^-2 m/s² = 5755 N
3. Wednesday: F = ma = 126,900 kg × 5.00 × 10^-2 m/s² = 6345 N
4. Thursday: F = ma = 113,700 kg × 5.00 × 10^-2 m/s² = 5685 N
5. Friday: F = ma = 125,850 kg × 5.00 × 10^-2 m/s² = 6292.5 N

Therefore, the order of the days showing the size of the force applied to the freight, from smallest to largest, is: Thursday, Tuesday, Friday, Monday, Wednesday.