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Kyle pours 3 2 ​ liter of water out of a beaker. he then pours 3 2 ​ liter of water into the beaker. what is the overall change in the amount of water in the beaker?

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Final answer:

Kyle's actions of pouring 3/2 liter out and then 3/2 liter into the beaker result in no overall change in the volume of water in the beaker, as the two amounts cancel each other out.

Step-by-step explanation:

Kyle pours 3/2 liter of water out of a beaker, then pours 3/2 liter of water into the beaker.

To determine the overall change in the amount of water in the beaker, we subtract the amount of water poured out from the amount of water poured in, which in this case would be 3/2 liter - 3/2 liter.

Since the amount poured out and the amount poured in are the same, they cancel each other out, resulting in no change in the volume of water in the beaker.

By considering the two actions as separate events, we don’t see any direct correlation to the provided examples showing how to solve for changes in volume, concentration, or moles in different contexts.

However, the concept remains the same – to find the change in volume, we take the final volume and subtract the initial volume. In Kyle's situation, after the two actions, the beaker's volume ends up the same as the initial amount, so the change in volume is zero liters.

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