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Marshall spins a prize wheel with 4 segments of equal size, one of which is labeled "winner."

Let X = the number of spins until Marshall wins a prize.
What is the probability that Marshall wins a prize on his 2nd spin?
Recall: P(X = k) = (1 - p)k-1p
Round to 4 decimal places
a. 0.1875
b. 0.1675
c. 0.1575
d. 0.1475

1 Answer

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Final answer:

The probability that Marshall wins a prize on his second spin of a prize wheel with 4 segments is 0.1875, using the geometric distribution formula. The correct answer is option a. 0.1875.

Step-by-step explanation:

The question asks about the probability that Marshall wins a prize on his second spin of a prize wheel with 4 equally-sized segments, one of which is labeled "winner." This is a problem in the subject of probability and can be solved using the geometric distribution formula:

P(X = k) = (1 - p)k-1p

Where p is the probability of winning on a single spin and k is the number of spins until a win occurs. In this case, p = 1/4 (since one out of four segments is a winner), and k = 2 (because we want to find the probability that he wins on the second spin). Plugging the values into the formula:

P(X = 2) = (1 - 1/4)2-1(1/4)

Calculating the probability:

P(X = 2) = (3/4)1(1/4) = 3/16

When converted to decimal form and rounded to four decimal places, the probability is:

P(X = 2) = 0.1875

Therefore, the correct option is a. 0.1875.

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