Final answer:
The correct answer to identify the for loop that would iterate 3 times is 'd. I and II only', as the first and second loops provided will iterate 4 times assuming lotNumLength is 3 while the third loop will iterate exactly 3 times.
Step-by-step explanation:
The student's question pertains to identifying the correct for loop that would iterate exactly 3 times to generate a lottery number. Since the exact value of lotNumLength is not provided, we will assume that lotNumLength is meant to represent the number 3, which is the number of times the loop must iterate. Let's analyze each loop:
- The first loop: for(int n = 1; n <= lotNumLength; n++) will iterate 4 times if lotNumLength is 3 (from 1 to 3, inclusive).
- The second loop: for(int n = 0; n <= lotNumLength; n++) will iterate 4 times as well if lotNumLength is 3 (from 0 to 3, inclusive).
- The third loop: for(int n = 0; n < lotNumLength; n++) is the correct loop that will iterate 3 times (from 0 to 2).
Therefore, the loops containing errors that will iterate more than 3 times, given that lotNumLength is 3, are the first and the second loops.
The correct answer is: d. I and II only.