Question

The capacity of a storage battery, such as those used in automobile electrical systems, is rated in ampere-hours . A battery can supply a current of for , or for , and so on.

a. What total energy can be supplied by a 11 v , 40 a⋅h battery if its internal resistance is negligible?

Answer 1

The total energy supplied by an 11-volt, 40 ampere-hour battery with negligible internal resistance is 1584000 joules or 440 watt-hours, found by multiplying the voltage, ampere-hour rating, and a conversion factor.

Step-by-step explanation:

The student asked about the total energy that can be supplied by an 11-volt, 40 ampere-hour (40 Ah) battery, assuming its internal resistance is negligible.

To find the total energy that a battery can supply, we have to use the relationship that energy (E in watt-hours) is equal to the product of voltage (V in volts), charge capacity (Q in ampere-hours), and a conversion factor to get the energy in joules (since 1 watt-hour is equivalent to 3600 joules).

Therefore, the energy can be calculated as E = V x Q x 3600. In this case, E = 11 volts x 40 ampere-hours x 3600 = 1584000 joules or 440 watt-hours. This is the maximum energy the battery can deliver if its internal resistance is truly negligible.