105k views
1 vote
Monika runs around a rectangular park with perimeter (3x + 1) m and Mehul runs around triangular park with perimeter (5x + 1) m. Who runs more and by how much?​

1 Answer

4 votes

Final answer:

Mehul runs more than Monika. The expressions for their park perimeters show Mehul's perimeter is greater by 2x meters.

Step-by-step explanation:

To determine who runs more between Monika and Mehul, we need to compare the perimeters of the parks they're running around. Monika runs around a rectangle with a perimeter given by the expression (3x + 1) meters, while Mehul runs around a triangular park with a perimeter represented by (5x + 1) meters. Since we don't have the actual values of the variable x, we can only compare the expressions to see who runs more.

Comparing the coefficients of x in both expressions, we see that Mehul's perimeter coefficient is greater (5 > 3), indicating that for the same value of x, Mehul will always have a greater perimeter to run. To find out by how much more Mehul runs, we subtract Monika's perimeter from Mehul's perimeter: ((5x + 1) - (3x + 1)) meters = (2x) meters. Therefore, Mehul runs 2x meters more than Monika, regardless of the value of x.

This comparison is similar to a problem where we compare areas of squares. For example, if Marta has a square with a side length of 4 inches and another square with dimensions twice as large, the larger square will have a side length of 8 inches. The area of the larger square is 8 inches × 8 inches = 64 square inches, which is four times the area of the smaller square (4 inches × 4 inches = 16 square inches). Just as Mehul runs a perimeter that is larger by a factor (in this case, 2x), the larger square's area is larger by a factor (in this case, the square of the scaling factor, which is 4).

User Mmsilviu
by
8.4k points