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A 16.2 kg block is pulled over a rough, horizontal surface by a constant force of 131 N acting at an angle of 25.9 degrees above the horizontal. The block is displaced 76.7 m, and the coefficient of kinetic friction is__

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Final answer:

The coefficient of kinetic friction is calculated using the horizontal force component, force of friction, normal force, and the fact that the block moves at a constant velocity on a horizontal surface.

Step-by-step explanation:

The question is asking for the coefficient of kinetic friction between a 16.2 kg block and a rough, horizontal surface. The block is being pulled by a force that has a horizontal component and a vertical component due to the angle of application. The coefficient of kinetic friction (μ_k) can be calculated using the net force on the block, the force of friction, and the normal force.

First, determine the horizontal component of the applied force (F_cosθ) and the vertical component (F_sinθ). Subtract the force of friction (f_k) from F_cosθ to find the net force, which in this case, because the block is moving at a constant velocity, is zero.

The normal force is a combination of the gravitational force (weight) and the vertical component of the applied force. Use the equation f_k = μ_k * N, where N is the normal force, to solve for μ_k.

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