Question

A 2.200 g sample of quinone,C₆H₄O₂, is burned in a bombcalorimeter whose total heat capacity is 7.854 kJ/°C. Thetemperature of the calorimeter increased from 23.38°C to 30.51°C. What is the heat of combustion pergram of quinone?

_______kJ/g

Answer 1

The heat of combustion per gram of quinone, C6H4O2, is 25.4659 kJ/g. This was calculated using the heat capacity of the bomb calorimeter and the observed temperature change due to the combustion of a 2.200 g sample of quinone.

Step-by-step explanation:

To calculate the heat of combustion per gram of quinone, we can use the equation:

q = C*D T

Where q is the heat transferred, C is the heat capacity of the calorimeter, and D T is the temperature change.

In this case, the heat transferred is equal to the heat of combustion of the quinone. Plugging in the given values, we get:

q = (7.854 kJ/°C)(30.51°C - 23.38°C)

q = 55.9839 kJ

To find the heat of combustion per gram, we divide the heat transferred by the mass of the quinone:

Heat of combustion per gram = 55.9839 kJ / 2.200 g

The heat of combustion per gram = 25.4463 kJ/g .