Final answer:
The reaction between hydrobromic acid (HBr) and manganese(III) hydroxide (Mn(OH)3) is an acid-base neutralization producing the soluble salt manganese(III) bromide (MnBr3) and water. The balanced chemical equation is 3 HBr(aq) + Mn(OH)3(s) → MnBr3(aq) + 3 H2O(l).
Step-by-step explanation:
To answer the question regarding the reaction between HBr(aq) and Mn(OH)3 (s), we first need to consider the nature of the reactants. Hydrobromic acid, HBr, is a strong acid that will dissociate completely in water to produce H+ ions and Br- ions, while manganese(III) hydroxide, Mn(OH)3, is an insoluble base that remains mostly undissociated. The expected reaction is an acid-base neutralization reaction, producing water and a salt.
The balanced chemical equation for the reaction is:
3 HBr(aq) + Mn(OH)3 (s) → MnBr3(aq) + 3 H2O(l)
In this equation, MnBr3 is assumed to be soluble in water and thus exists in the aqueous phase. The phases are represented by (aq) for aqueous and (l) for liquid. The solid manganese(III) hydroxide does not dissociate and is indicated by the phase (s). It's important to note that the stoichiometry of the reaction shows that three moles of HBr are needed to react with one mole of Mn(OH)3 to maintain charge balance and produce one mole of MnBr3 and three moles of water.