Given:
One midsegment of an equilateral triangle.
To find:
The ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths.
Solution:
All sides of an equilateral triangle are same.
Let a be the each side of the equilateral triangle.
Length of the midsegment is equal to the half of the non included side or third side.
![Midsegment=(a)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/zude4rbd7e0gwb1i3bvrbz372mnyfb5789.png)
The sum of two side is
![a+a=2a](https://img.qammunity.org/2022/formulas/mathematics/high-school/g1qhbi5g8i8wgkvjtda5bzbhjdpxd14jds.png)
Now, the ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths is
![\text{Required ratio}=\frac{\text{Length of midsegment}}{\text{sum of two sides}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/16oi07974safwsw7a7uvippag7hr93byu0.png)
![\text{Required ratio}=((a)/(2))/(2a)](https://img.qammunity.org/2022/formulas/mathematics/high-school/22sxtcs3pdcaaj6lrm5bijiqujvj1lgogd.png)
![\text{Required ratio}=(a)/(4a)](https://img.qammunity.org/2022/formulas/mathematics/high-school/21j9ckps3urq43ekwh9ap4liz0rolg7gqs.png)
![\text{Required ratio}=(1)/(4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/2isv49oppxwkjqsad5tgq4b2i3hzwwkn47.png)
![\text{Required ratio}=1:4](https://img.qammunity.org/2022/formulas/mathematics/high-school/5bkdgr19ob8ryuf1kt3s87oirvjwkyhnd3.png)
Therefore, the ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths is 1:4.