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For the dissociation of nitrogen according to N2 == 2N Calculate

The equilibrium partial pressure of N in nitrogen gas at 3000 K and a total pressure of 1 atm.

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Final answer:

To calculate the equilibrium partial pressure of individual nitrogen atoms from N2 gas at 3000 K and 1 atm, the equilibrium constant for the temperature is required, which is not provided, making the calculation impossible to complete.

Step-by-step explanation:

The dissociation of nitrogen N2 into individual nitrogen atoms (N) at a high temperature is an equilibrium process represented by N2 ⇌ 2N. To calculate the equilibrium partial pressure of nitrogen atoms (N) in nitrogen gas at 3000 K and a total pressure of 1 atm, we would need the equilibrium constant (Kp) for this dissociation at 3000 K. Unfortunately, the equilibrium constant is not provided, rendering the calculation incomplete.

In equilibrium calculations, one would typically use the initial pressures of the reactants and products, along with the equilibrium constant, to determine the changes in pressure that occur as the system reaches equilibrium. These changes are applied to find final partial pressures of all species involved.

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