Final answer:
To estimate the molecular weight of a virus like the bushy stunt virus, additional information is required. The density, diffusion coefficient, and viscosity of water are not sufficient to make this estimation directly. Stokes' law can be used to determine the relationship between the particle size and terminal velocity but doesn't provide the molecular weight without further data.
Step-by-step explanation:
To estimate the molecular weight (MW) of bushy stunt virus, you need additional information beyond the given density, diffusion coefficient, and the viscosity of water. However, Stokes' law can be used to determine the size of the virus particle which is indirectly related to its molecular weight. Stokes' law relates terminal settling velocity of a spherical particle through a fluid with its size, the fluid's viscosity, and the difference in density between the particle and the fluid.
In other scenarios where you have the required data, you could use the formula from Stokes' law Fs = 6πηrν, where Fs is the drag force, η is the fluid viscosity, r is the radius of the particle, and v is the velocity of the particle. However, the question provided doesn't include enough details to perform such a calculation for the bushy stunt virus.
To calculate the terminal velocity of a spherical bacterium falling through water, you would employ the relationship between the drag force and the gravitational force at terminal velocity (where they are equal) and use Stokes' law to solve for v.