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A wheel rotates with an initial angular angular velocity ωi. It experiences a constant angular acceleration α and reaches a final angular speed ωf=75.9 rad/s in 10 s. During this time, the wheel completes 37.0 revolutions. Find the value of the angular acceleration α and the initial angular velocity ωi.

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Final answer:

The value of the angular acceleration α is approximately -0.314 rad/s² and the initial angular velocity ωi is 78.0 rad/s.

Step-by-step explanation:

To find the angular acceleration (α) and the initial angular velocity (ωi), we can use the following equations:

ωf = ωi + αt

θ = ωi*t + (1/2)*α*t^2

Given that ωf = 75.9 rad/s, t = 10 s, and θ = 37.0 revolutions = 2π*37.0 rad, we can substitute these values into the equations:

75.9 = ωi + α*10

2π*37.0 = ωi*10 + (1/2)*α*10^2

Simplifying these equations, we get:

ωi + 10α = 75.9

37π = 10ωi + 50α

Now, we have a system of equations that we can solve for ωi and α. Subtracting the first equation from the second equation, we get:

37π - ωi = 10ωi + 50α - 75.9

Combining like terms, we get:

11ωi + 50α = 37π - 75.9

Substituting the value of ωi from the first equation into the second equation, we get:

11(75.9 - 10α) + 50α = 37π - 75.9

Simplifying and rearranging the equation, we obtain:

527.9 - 110α + 50α = 37π - 75.9

Combining like terms, we get:

527.9 - 60α = 37π - 75.9

Subtracting 527.9 from both sides and rearranging the equation, we have:

-60α = 37π - 603.8

Dividing both sides by -60, we get:

α ≈ -0.314 rad/s²

Substituting this value of α into the first equation, we can solve for ωi:

75.9 = ωi + (-0.314)*10

Simplifying the equation, we get:

ωi = 78.0 rad/s

Therefore, the value of the angular acceleration α is approximately -0.314 rad/s² and the initial angular velocity ωi is 78.0 rad/s.

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