Final answer:
The mass of water displaced by the rock when submerged in water is 213 grams, determined by subtracting the rock's apparent submerged mass (357 g) from its mass in air (570 g), according to Archimedes' principle.
Step-by-step explanation:
The mass of water displaced by the rock when submerged in water can be determined using Archimedes' principle, which states that the buoyant force on a submerged object is equal to the weight of the fluid it displaces.
Therefore, to find the mass of water displaced, you subtract the apparent mass of the rock when submerged from its mass in air.
In this case, the rock has a mass of 570 g in air and an apparent mass of 357 g when submerged. The mass of water displaced is then calculated as follows:
Mass of rock in air - Apparent mass of rock submerged = Mass of water displaced
570 g - 357 g = 213 g
So, the mass of water displaced by the rock is 213 grams.