Final answer:
To determine the tension in the rope for a ball weighing 50 N when held at an angle, we presume it is stationary and that the tension is counterbalancing the gravitational force, leading to an approximate tension of 50 N.
Step-by-step explanation:
To determine the tension in the pulling rope when a ball weighing 50 N is held at a 20° angle, we must consider the forces acting along the rope. Since the question specifies the weight of the ball but not the details of horizontal or vertical components, and there is no information on the rope's length or the height at which the ball is held, the tension in the rope would be a direct counterbalance to the weight of the ball if it's being held stationary in a gravitational field (ignoring any additional forces due to the angle).
If we consider a similar scenario where a 5.00-kg mass is suspended by a rope, we find that the tension in the rope is calculated as T = mg = (5.00 kg)(9.80 m/s²) = 49.0 N. This is because tension in a rope supporting a stationary mass must balance the gravitational force (weight) acting on the mass, as per Newton's second law of motion where the net force (Fnet) is zero.
In the case of our 50 N ball, assuming it is stationary and only subject to gravitational forces, the tension in the rope would be nearly 50 N as well, slightly adjusted for the 20° angle. However, due to the lack of specific information regarding the system's dynamics or any components of the force at the specified angle, we're limited to stating that the tension would approximate the gravitational force acting on the ball.