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A compound microscope has a barrel length of l=161 mm and an objective with a 4.01 mm focal length. the total angular magnification of the microscope is

User Bigsby
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Final answer:

The question involves computing the total angular magnification of a compound microscope using the optic principles of physics. Information about the eyepiece is necessary for a precise calculation of total magnification, which involves the magnifications of both the objective and the eyepiece lenses.

Step-by-step explanation:

The question at hand pertains to the calculation of the total angular magnification of a compound microscope with given focal lengths for the objective lens and known barrel length. This topic is grounded in optics, a branch of physics that deals with the behavior and properties of light, including its interactions with matter and the construction of instruments that use or detect it.

In a compound microscope, the total magnification is the product of the magnifications provided by the objective lens and the eyepiece. The magnification of the objective lens, mobj, can be calculated using the thin-lens equation for magnification. However, the complete calculation for total magnification requires additional information, such as the focal length of the eyepiece, which is not provided here. Nonetheless, an understanding of these concepts allows us to comprehend that adjustments to the positioning of the lenses and their respective focal lengths directly influence the magnification observable when using a compound microscope.

For instance, if an objective lens is moved closer to the specimen, which means that the distance between the object and the objective lens (dobj) is less than the focal length (fobj), it would lead to an increased magnification since it would generate a larger image of the specimen. Conversely, increasing the distance between the object and the objective lens reduces magnification.

User Taquanna
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