Question

As part of a safety investigation, two 1900 kg cars traveling at 22 m/s are crashed into different the average force exerted on the car that hits a line of water barrels and takes 1.8 s to stop. express your answer with the appropriate units.

Answer 1

The average force exerted on a 1900 kg car that hits water barrels and stops in 1.8 seconds from a velocity of 22 m/s is calculated using Newton's second law and comes out to be 23,218 N in the direction opposite to the car's initial motion.

Step-by-step explanation:

To determine the average force exerted on a car that hits water barrels, we can use the formula F = ma, where F is the force, m is the mass of the car, and a is the acceleration (or deceleration in this case). The deceleration can be found using the formula: a = ∆v / ∆t, which translates to change in velocity (∆v) over change in time (∆t).

To calculate the force exerted on the 1900 kg car that comes to a stop after 1.8 seconds from a velocity of 22 m/s:

• Calculate the deceleration: a = ∆v / ∆t = (-22 m/s) / 1.8 s = -12.22 m/s² (the negative sign indicates deceleration).
• Apply Newton's second law to find the force: F = ma = 1900 kg × -12.22 m/s² = -23,218 N.

The negative sign indicates the direction of the force is opposite to the direction of motion. Therefore, the average force exerted on the car by the water barrels is 23,218 N in the direction opposite to the car's initial motion.