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An electron moving at right angles to a 0.13 Tmagnetic field experiences an acceleration of 5.6×10¹⁵ m/s² .

Whats the electrons speed?

User Ksbg
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1 Answer

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Final answer:

To find the speed of the electron, use the formula for centripetal acceleration by rearranging the equation for magnetic force. The speed of the electron is 1.75x10^7 m/s.

Step-by-step explanation:

To find the speed of the electron, we can use the formula for centripetal acceleration:

a = v^2/r

where a is the acceleration, v is the speed, and r is the radius of the circular path. We are given the acceleration (5.6x10^15 m/s^2) and the magnetic field strength (0.13 T).

Using the equation for the magnetic force experienced by a charged particle:

F = qvB

where F is the magnetic force, q is the charge, v is the velocity, and B is the magnetic field strength. We can rearrange this equation to solve for the speed (v): v = F / (qB)

Substituting the given values for the magnetic force (5.6x10^15 N) and charge of an electron (-1.6x10^-19 C), and the magnetic field strength (0.13 T), we can calculate the speed of the electron to be 1.75x10^7 m/s.

User Michael Klement
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