Final answer:
The work done by the escalator on a person with a mass of 63 kg carried 4.5 meters upward is calculated using the formula W = m × g × h, resulting in 2770.45 joules.
Step-by-step explanation:
The question pertains to the amount of work done by the escalator to lift a person from the lower level to the upper level in an airport terminal, so we will calculate that using the concept of work in the context of physics.
To determine the work done by the escalator, we can use the formula for work done against gravity, which is W = m × g × h, where W is the work done in joules (J), m is the mass of the person in kilograms (kg), g is the acceleration due to gravity (approximately 9.81 m/s²), and h is the height difference in meters (m).
In this specific problem, the mass of the person (m) is given as 63 kg, and the height the escalator raises the person (h) is 4.5 m. Inserting these values into the formula along with the constant value of g gives:
W = 63 kg × 9.81 m/s² × 4.5 m,
Resulting i
W = 2770.45 J.
Therefore, the escalator does 2770.45 joules of work on the person when carrying them from the lower level to the upper level.