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During a process a system absorbs 710 J of heat and does work? The change in internal energy for the process is 460 J. What is the work done by the system?

User Frazz
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Final answer:

The work done by the system is 250 J, calculated using the first law of thermodynamics, which states that the change in internal energy is equal to the heat added to the system minus the work done by the system.

Step-by-step explanation:

The question pertains to the first law of thermodynamics, which relates to the principle of conservation of energy in physics. According to this law, the change in internal energy of a system (ΔU) is equal to the heat (Q) added to the system minus the work (W) done by the system on its surroundings.

Mathematically, this is expressed as ΔU = Q - W.

In the stated scenario, the system absorbs 710 J of heat and has a change in internal energy of 460 J. To find the work done by the system, we rearrange the first law of thermodynamics to solve for W:

W = Q - ΔU. Upon substituting the values into the equation, we get W = 710 J - 460 J, which simplifies to W = 250 J. Therefore, the work done by the system is 250 J.

User GirishK
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