Final answer:
Using row operations on the system of equations leads to a single unique solution, which is (-25, -2, 30). Therefore, the correct option is A).
Step-by-step explanation:
To solve the system of equations using row operations, we start by setting up our augmented matrix:
[ 1 1 -1 | 7]
[ 2 -1 1 | -10]
[ 1 -4 3 | -43]
We want to create zeros below the leading 1 in the first column of the first row, to start forming an upper triangular matrix. This can be achieved by performing the following row operations:
- R2 = R2 - 2*R1
- R3 = R3 - R1
After performing these operations, our matrix should look like this:
[ 1 1 -1 | 7]
[ 0 -3 3 | -24]
[ 0 -5 4 | -50]
Next, we create a zero below the leading term in the second column of the second row:
- R3 = R3 + (5/3)*R2
Our matrix now:
[ 1 1 -1 | 7]
[ 0 -3 3 | -24]
[ 0 0 -1 | -30]
From here, we can back-substitute to solve for Z, then Y, and finally X. Doing so yields the following solutions:
Therefore, there is one solution to the system and the solution is (-25, -2, 30).
We can mention the correct option in the final part of our solution process, which is:
A. There is one solution. The solution is (-25, -2, 30)