Final answer:
To find (f \circ g)(x), substitute g(x) into f(x), resulting in (f \circ g)(x) = x^2 - 2x - 1. The domain of (f \circ g)(x) is all real numbers due to the nature of quadratic functions.
Step-by-step explanation:
To find the formula for (f \circ g)(x), you need to compose the functions f and g. That means you'll substitute g(x) into f(x). Starting with the given functions:
f(x) = x^2 - 2
g(x) = x - 1
The composition of f and g, denoted as (f \circ g)(x), is:
(f \circ g)(x) = f(g(x)) = f(x - 1)
Now, substitute x - 1 into f(x):
(f \circ g)(x) = (x - 1)^2 - 2
Expand and simplify:
(f \circ g)(x) = x^2 - 2x + 1 - 2
(f \circ g)(x) = x^2 - 2x - 1
The domain for the simplified function (f \circ g)(x), which is a quadratic function, is all real numbers, or (-\infty, \infty), since there are no restrictions on x that would prevent the function from being defined.