Final answer:
The largest unsigned integer in base 2 with n digits is obtained by having all n digits as 1, which is equal to the decimal value of 2^n - 1.
Step-by-step explanation:
The largest unsigned integer in base 2 with n digits is a value where each digit is a 1. In binary, the value of a fully 'saturated' number (one where all digits are the maximum value, which is 1) would be 2n - 1. This formula arises because binary is a base-2 system, so each digit represents a power of 2. To get the maximum number, you sum all the powers of 2 from 20 (which is 1) up to 2n-1. This sum is 2n - 1, which, for n digits, would look like 111...111 where there are n ones.