Question

What does the following functoin do for a given Linked List with first node as head? void fun1(struct node* head) { if(head == NULL) return; fun1(head->next); printf("%d ", head->data); }

Answer 1

The given function is a recursive function that prints the data of each node in a linked list in reverse order.

Step-by-step explanation:

The given function is a recursive function that prints the data of each node in a linked list in reverse order. Here is how the function works:

1. First, it checks if the head pointer is NULL. If it is, it means we have reached the end of the linked list and there is nothing more to print, so the function returns.
2. If the head pointer is not NULL, the function calls itself recursively with the next node in the linked list as the new head.
3. This recursive call keeps happening until we reach the last node in the linked list.
4. Once we reach the last node, the function prints the data of that node.
5. Then, the recursive calls start returning one by one, printing the data of each previous node in reverse order.

For example, if we have a linked list with nodes containing data values 1, 2, 3, and 4, the function will print: 4 3 2 1.