In △JLK , MO = 29, ON = 32, and NM = 38. Find the missing lengths listed below and the perimeter of △JLK . JK = LK = LJ = Perimeter of △JLK =

98,362 views

40 votes

In △JLK

, MO = 29, ON = 32, and NM = 38. Find the missing lengths listed below and the perimeter of △JLK
.

JK =

LK =

LJ =

Perimeter of △JLK
=

2.7k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

22 votes

Answer:

58, 76, 64, 198

Explanation:

Using the triangle midsegment theorem,
JK=58, LK=76 , and
LJ=64 .

So, the perimeter of
$\triangle JLK=58+76+64=198$

2.7k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers