To balance the equation B2O3(s) + HF(l) - BF3(g) + H2O(l), start by counting the number of atoms of each element on both sides of the equation. Then, balance the B and H atoms first, followed by the F and O atoms. The balanced equation is 3 B2O3(s) + 6 HF(l) → 2 BF3(g) + 3 H2O(l).
To balance the equation B2O3(s) + HF(l) → BF3(g) + H2O(l), we need to make sure that the number of atoms of each element is the same on both sides of the equation. Here's how to balance the equation:
Step 1: Start by counting the number of atoms of each element on both sides of the equation:
Reactant side: 2 B, 3 O, 1 H, 1 F
Product side: 1 B, 1 F, 2 H, 1 O
Step 2: Balance the elements one at a time:
- Start with balancing the B atoms by placing a coefficient of 2 in front of BF3 in the product side: B2O3(s) + 6 HF(l) → 2 BF3(g) + H2O(l)
- Next, balance the H atoms by placing a coefficient of 3 in front of H2O in the product side: B2O3(s) + 6 HF(l) → 2 BF3(g) + 3 H2O(l)
- Finally, balance the F and O atoms by placing coefficients of 6 and 3, respectively, in front of HF and B2O3 in the reactant side: 3 B2O3(s) + 6 HF(l) → 2 BF3(g) + 3 H2O(l)
The balanced equation is 3 B2O3(s) + 6 HF(l) → 2 BF3(g) + 3 H2O(l).