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the equation of line p is y-10=1/7(x-1) line q includes the point (1, 1) and is parallel to line p what is the equation of line q?

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Final answer:

Line q is parallel to line p and passes through the point (1, 1). Since parallel lines have the same slope, line q has a slope of 1/7. The equation of line q in point-slope form is y - 1 = 1/7(x - 1).

Step-by-step explanation:

Line q is parallel to line p, which means both lines have the same slope.

The equation of line p is given as y - 10 = 1/7(x - 1). Line p's slope is 1/7.

Since line q passes through the point (1, 1) and is parallel to p, it must have the same slope of 1/7.

To find the equation of line q, we use the point-slope form of the equation of a line, which is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.

Plugging in the slope 1/7 and the point (1, 1), we get:

y - 1 = 1/7(x - 1)

This is the equation of line q.

User Siraj Syed
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