Question

The primary coil of a transformer makes 40 turns around the iron core and the secondary coil of that transformer makes 600 turns. If the primary voltage is 120 V, what is the secondary voltage (in V)?

Answer 1

Using the transformer equation, the secondary voltage of a transformer with a 120 V primary voltage, 40 turns on the primary coil, and 600 turns on the secondary coil is calculated to be 1800 V.

Step-by-step explanation:

The secondary voltage of a transformer given the number of turns in the primary and secondary coils and the primary voltage. According to the transformer equation, the ratio of the secondary to primary voltages is equal to the ratio of the number of turns in their respective coils. In this case, the primary coil of the transformer makes 40 turns, and the secondary coil makes 600 turns, with the primary voltage being 120 V.

To calculate the secondary voltage (Vs), we apply the transformer equation:

Vs/Vp = Ns/Np

where Vs is the secondary voltage, Vp is the primary voltage (120 V), Ns is the number of turns on the secondary coil (600 turns), and Np is the number of turns on the primary coil (40 turns).

Rearranging the equation to solve for Vs gives us:

Vs = Vp * (Ns/Np)

Substituting the numbers:

Vs = 120 V * (600 turns / 40 turns)

Vs = 120 V * 15

Vs = 1800 V

Therefore, the secondary voltage of the transformer is 1800 V.