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How many electrons must be shown in the Lewis structure of the hydroxide ion? OH⁻ (note the negative charge of the ion)

User Nagy
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Final answer:

The Lewis structure of the hydroxide ion (OH⁻) consists of the oxygen atom bonded to a hydrogen atom. The total number of valence electrons in the hydroxide ion is 8.

Step-by-step explanation:

The Lewis structure of the hydroxide ion (OH⁻) consists of the oxygen atom bonded to a hydrogen atom. The total number of valence electrons in the hydroxide ion is 8. To represent the ion with a negative charge, we add an extra electron to the central atom. So, we need to show 8 electrons in the Lewis structure of the hydroxide ion.

User John Garreth
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