Final Answer:
NO₂⁻ and NO₃⁻ contain double bonds and have trigonal planar shapes. So, the correct options are A. NO₂⁻ and C. NO₃⁻.
Step-by-step explanation:
The molecules and ions in question contain double bonds and exhibit trigonal planar shapes due to their molecular geometry. NO₂⁻ possesses a double bond between nitrogen and one oxygen atom, with a lone pair on nitrogen, resulting in a trigonal planar shape. Similarly, NO₃⁻ features a double bond between nitrogen and one oxygen atom, along with two other oxygen atoms bonded through single bonds, leading to a trigonal planar configuration due to the arrangement of its atoms. SO₃, however, does not contain double bonds; it comprises three double bonds between sulfur and oxygen atoms but adopts a trigonal planar shape based on its bonding and lone pair arrangement.
In both NO₂⁻ and NO₃⁻, the presence of a double bond contributes to the planar shape, as it influences the spatial arrangement of atoms and lone pairs around the central atom. The double bonds within these molecules cause a repulsion that arranges the surrounding atoms in a trigonal planar manner. Meanwhile, SO₃ contains three double bonds, yet its trigonal planar shape arises due to the arrangement of the bonding and non-bonding electron pairs around the sulfur atom, creating a symmetrical, planar structure. Therefore, while all three molecules exhibit a trigonal planar shape, only NO₂⁻ and NO₃⁻ contain double bonds, influencing their overall geometry.
So, the correct options are A. NO₂⁻ and C. NO₃⁻.