158k views
2 votes
In a mixture of N₂ and O₂ gases, the mole fraction of N2 is 0.700. what is the partial pressure of O₂ if the total pressure of the mixture is 1.42 atm?

A. 0.211 atm
B. 0.493 atm
C. 0.426 atm
D. 0.994 atm

1 Answer

5 votes

Final answer:

The partial pressure of O2 in the mixture of N2 and O2 gases is 0.426 atm. In this case, the mole fraction of N2 is given as 0.700, which means the mole fraction of O2 is 0.300. Therefore, the correct answer is C.

Step-by-step explanation:

The partial pressure of O2 can be calculated using Dalton's law.

The partial pressure of O2 is proportional to its mole fraction, which is the ratio of the moles of O2 to the total moles of gas in the mixture.

In this case, the mole fraction of N2 is given as 0.700, which means the mole fraction of O2 is 0.300.

Since the total pressure of the mixture is given as 1.42 atm, the partial pressure of O2 can be calculated as 0.300 times 1.42 atm, which equals 0.426 atm.

Therefore, the correct answer is C.

User Cascal
by
7.7k points