Question

Given the following Matlab code: v=4; while v<8; y=v+2; v=v+2; end; disp(y) What is the output from the disp(y) command?

a) 10
b) 12
c) 8
d) 6

Answer 1

The Matlab code runs a while loop that increments v by 2 in each iteration until v is no longer less than 8, at which point it displays y, which is always v+2. The output from the disp(y) command will be 8 since the loop ends when v reaches 8, making y equal to 6+2 before the loop ends.

Step-by-step explanation:

The question pertains to the output from the disp(y) command after executing a loop in the provided Matlab code. Let's go through the code step by step:

• v is initialized to 4
• The while loop continues as long as v is less than 8
• In each iteration, y is set to v + 2, and v is increased by 2
• When v becomes 8, the loop ends
• The last value of y which is v + 2 before v becomes 8 is displayed

During the first iteration, v is 4, y is set to 6. During the second iteration, v becomes 6, y is set to 8. There will be no third iteration because v becomes 8, which breaks the loop condition.

Thus, the code will output 8, which makes the correct answer c) 8. This value is displayed using the disp(y) command after the loop terminates.