Question

What is the output of the following code:

Circle c1 = new Circle(3);
Circle c2 = new Circle(3);
c1.setRadius(4);
System.out.println(c2.getRadius());
a) 3
b) 8
c) 6
d) 4

Answer 1

The output of the code is '3' because only the radius of c1 is changed to 4, while c2 remains with the original radius value of 3.

Step-by-step explanation:

When analyzing the output of the given code involving instances of a Circle class, we must consider the actions being taken on c1 and c2 separately. Initially, both circles are created with a radius of 3. However, c1.setRadius(4) is then called, which changes the radius of c1 but does not affect c2. Therefore, when System.out.println(c2.getRadius()) is executed, the output is the current radius of c2, which remains unchanged at 3. The correct answer is (a) 3.