Final answer:
The protein with a pI of 9.2 will migrate towards the cathode when subjected to an electric field at a pH of 10.0, because it will have a net negative charge.
Step-by-step explanation:
The correct statement regarding the electrophoretic migration of a protein with a pI of 9.2 in an electrical field with a pH set at 10.0 is that the protein will migrate towards the cathode. This is because the isoelectric point (pI) of a protein is the pH at which it has no net charge. When the pH of the electrical field is higher than the protein's pI, the protein will have a net negative charge and thus migrate towards the positive electrode (anode). However, in this case, since the pH is set at 10.0, the protein will have a net negative charge and will move towards the cathode, which is the negative electrode.