Question

A block weighing 30 kg is being pulled by a rope horizontally with a force of 125 N what is the minimum downward force on the box in the figure that will keep it from slipping the coefficient of static, and kinetic friction between the box and the floor are 0.32 and 0.22 respectfully

Answer 1

The minimum downward force needed to keep the block from slipping is 94.08 N.

Step-by-step explanation:

To find the minimum downward force on the block that will keep it from slipping, we need to consider the forces acting on the block. The downward force is the weight of the block, which is equal to the mass multiplied by the acceleration due to gravity. In this case, the weight is 30 kg multiplied by 9.8 m/s², giving a value of 294 N.

The frictional force opposing the motion is equal to the coefficient of static friction multiplied by the normal force. The normal force is equal to the weight of the block since it is resting on a flat surface. Therefore, the normal force is also 294 N.

Using the coefficient of static friction of 0.32, the frictional force is calculated as 0.32 multiplied by 294 N, giving a value of 94.08 N. To prevent the block from slipping, the minimum downward force should exceed the frictional force, which is 94.08 N in this case.