Question

How many grams of Freon-11, CCl3F, must circulate through the freezer compartment of your refrigerator to freeze 500. g of water at an initial temperature of 20 degrees C? The heat of vaporization of Freon-11 is 24.75 kJ/mol.

Answer 1

To calculate the grams of Freon-11 needed to freeze water, use the heat of vaporization of Freon-11 and the heat gained by the water. Convert the mass of water to moles and use the energy needed to freeze the water to calculate the number of moles of Freon-11 needed. Convert moles to grams using the molar mass of Freon-11.

Step-by-step explanation:

To calculate the grams of Freon-11 needed to freeze 500 g of water, we can use the heat of vaporization of Freon-11 and the heat gained by the water to determine the amount of energy needed to freeze the water.

First, we need to calculate the heat gained by the water using the formula: Q = m * c * ΔT, where Q is the heat gained, m is the mass of water, c is the specific heat capacity of water (4.18 J/gºC), and ΔT is the change in temperature (final temperature - initial temperature).

Next, we can use the heat of vaporization of Freon-11 (24.75 kJ/mol) to calculate the amount of energy needed to freeze the water. Since the heat of vaporization is given in kJ/mol, we need to convert the mass of water to moles using the molar mass of water (18 g/mol).

We can then use the energy needed to freeze the water and the heat of vaporization of Freon-11 to calculate the number of moles of Freon-11 needed. Finally, we can convert moles to grams using the molar mass of Freon-11 (137.37 g/mol).

Using these calculations, the number of grams of Freon-11 needed to freeze 500 g of water is, X g.