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What quantity of heat is required to melt 500. g of ice at 0 C then heat the resulting water to steam at 100 C ?

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Final answer:

To calculate the quantity of heat required to melt ice at 0°C and then heat the resulting water to steam at 100°C, you can use the specific heat capacities and heat of fusion of water.

Step-by-step explanation:

To calculate the quantity of heat required to melt ice at 0°C and then heat the resulting water to steam at 100°C, we need to consider the different stages of the process and use the specific heat capacities and heat of fusion of water.

  1. First, we calculate the heat required to melt the ice using the heat of fusion, which is 334 J/g. Multiply the mass of the ice (500 g) by the heat of fusion to get the quantity of heat required to melt the ice.
  2. Next, we calculate the heat required to heat the resulting water from 0°C to 100°C using the specific heat capacity of water, which is 4.18 J/g°C. Multiply the mass of the water (500 g) by the specific heat capacity and the change in temperature (100°C) to get the quantity of heat required.
  3. Add the heat required to melt the ice to the heat required to heat the water to get the total quantity of heat required.
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